Before the midterm
Assuming a continuous function is differentiable
The habit: A derivative at a point forces the graph to be unbroken there, but not the reverse: |x| is unbroken at 0 and has a corner, so no slope.
5 practice questions are built to catch it, in 3 topics.
See it fail in a figure: Where there is no slope, in the definition of the derivative lesson
What it looks like
A question from the definition of the derivative, with the answer this slip gives beside the right one.
The function is piecewise linear: its graph is made of straight segments joining , , and , in that order, as shown. Which statement about its derivative is correct?
- With the slip
- , , , and
- Worked through
- , , , and does not exist
The graph is unbroken at x = 1, but it turns a corner there: slope 2 just to the left, 0 just to the right. No single tangent fits a corner, and an average of the two slopes is not one.
Where it comes up
- Continuity2 questions
- The definition of the derivative2 questions
- Exponential and trigonometric functions1 question
Practise against it
Each of these has an answer this slip gives. Work them on paper: if you fall into it, the verdict names it and the question comes back in review.
- 01A function is continuous at , and . Which of the following must be true?
ContinuityIntroductory
- 03Let . Which statement about at is correct?
The definition of the derivativeStandard
- 04Let . Which statement about at is true?
Exponential and trigonometric functionsChallenging