Skip to content

Before the midterm

Checking the limit but not the value

The habit: Continuity at a point needs the limit and the value to exist and to agree.

4 practice questions are built to catch it, in 1 topic.

See it fail in a figure: The value counts too, in the continuity lesson

Practise against it: 3 questions

What it looks like

A question from continuity, with the answer this slip gives beside the right one.

Standard2 marks · 4 min

The graph of a function ff is shown. Of x=−3x = -3, x=−1x = -1, x=1x = 1 and x=3x = 3, which set lists exactly the ones at which ff is not continuous?

The graph of y = f(x) for x from −4 to 5, with a dashed vertical line at x = −3. Left of the dashed line the curve starts at (−4, 2) and climbs more and more steeply as it nears x = −3, reaching the top of the window. Right of the dashed line a second piece starts at the top of the window close to x = −3, falls through (−2, 2), and ends at a filled point at (−1, 1). Directly above that, an open circle at (−1, 3) starts a V made of two straight lines: it falls to a sharp corner at (1, 1), then rises through an open circle at (3, 3) to (5, 5). A filled point sits at (3, 5), above that open circle.-4-3-2-112345-1123456
With the slip
{−3, −1}\displaystyle \{-3,\ -1\}
Worked through
{−3, −1, 3}\displaystyle \{-3,\ -1,\ 3\}

At x = 3 the graph approaches the open circle at height 3 from both sides, so the limit exists, but the filled point puts f(3) = 5. A limit that exists is not enough: it must equal the value.

See the worked solution

Where it comes up

Practise against it

Each of these has an answer this slip gives. Work them on paper: if you fall into it, the verdict names it and the question comes back in review.

Start the set