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Before the midterm

Dividing by a variable that could be zero

The habit: Factor instead, or handle the case where it vanishes on its own, so that no candidate is lost.

4 practice questions are built to catch it, in 4 topics.

Practise against it: 3 questions

What it looks like

A question from continuity, with the answer this slip gives beside the right one.

Challenging3 marks · 5 min

The join of the function below sits at x=cx = c, and the constant cc also appears in the first piece. Find every value of cc that makes ff continuous everywhere.

f(x)={cx2,x≤c9x,x>cf(x) = \begin{cases} cx^{2}, & x \leq c \\[4pt] 9x, & x > c \end{cases}
With the slip
c=3 only\displaystyle c = 3 \text{ only}
Worked through
c=−3, c=0 or c=3\displaystyle c = -3,\ c = 0 \text{ or } c = 3

Two roots lost: dividing c³ = 9c by c assumes c ≠ 0, and c² = 9 has a negative root as well as a positive one.

See the worked solution

Where it comes up

Practise against it

Each of these has an answer this slip gives. Work them on paper: if you fall into it, the verdict names it and the question comes back in review.

Start the set