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Before the midterm

Misapplying a logarithm rule

The habit: A multiple in the exponent becomes a power: e2 log 3 = (elog 3)² = 9.

9 practice questions are built to catch it, in 5 topics.

Practise against it: 6 questions

What it looks like

A question from the chain rule and logarithms, with the answer this slip gives beside the right one.

Introductory2 marks · 3 min

Logarithmic differentiation of the function below starts by writing log⁡f(x)\log f(x) as a sum. Which expression equals log⁡f(x)\log f(x) for x>13x > \tfrac{1}{3}?

f(x)=(x2+1)4x (3x−1)2f(x) = \frac{\left(x^{2} + 1\right)^{4}}{\sqrt{x}\,(3x - 1)^{2}}
With the slip
4log⁡(x2)+4log⁡1−12log⁡x−2log⁡(3x−1)\displaystyle 4\log\left(x^{2}\right) + 4\log 1 - \tfrac{1}{2}\log x - 2\log(3x - 1)
Worked through
4log⁡(x2+1)−12log⁡x−2log⁡(3x−1)\displaystyle 4\log\left(x^{2} + 1\right) - \tfrac{1}{2}\log x - 2\log(3x - 1)

x² + 1 is a sum, not a product, so log(x² + 1) does not split into log(x²) + log 1. Only its fourth power comes down.

See the worked solution

Where it comes up

Practise against it

Each of these has an answer this slip gives. Work them on paper: if you fall into it, the verdict names it and the question comes back in review.

Start the set