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Before the midterm

Misjudging the number of real roots

The habit: The degree only bounds the count; the turning points and the sign of the function there decide it.

8 practice questions are built to catch it, in 5 topics.

Practise against it: 6 questions

What it looks like

A question from continuity, with the answer this slip gives beside the right one.

Standard3 marks · 4 min

The join of the function below sits at x=cx = c, where cc is a constant. Find every value of cc that makes ff continuous everywhere, and enter the sum of those values.

f(x)={2x2−1,x≤c7x−4,x>cf(x) = \begin{cases} 2x^{2} - 1, & x \leq c \\[4pt] 7x - 4, & x > c \end{cases}
With the slip
3\displaystyle 3
Worked through
c=12 or c=3,sum 72\displaystyle c = \frac{1}{2} \text{ or } c = 3, \quad \text{sum } \frac{7}{2}

c = 3 is one root, but the condition is a quadratic in c, and it has two: find the other.

See the worked solution

Where it comes up

Practise against it

Each of these has an answer this slip gives. Work them on paper: if you fall into it, the verdict names it and the question comes back in review.

Start the set