- Difficulty
- Standard
- Suggested time
- 4 min
- Marks
- 2
Optimization in two variables and Lagrange multipliers practice question 11
A student uses Lagrange multipliers to find the maximum value of the function below on the circle , as shown. Find the first line that is wrong.
Check each line against the system it came from: does it follow, and does it keep every solution of the three equations?
Dividing by an expression is only allowed when that expression cannot be zero. Is that guaranteed on every line?
Write the first condition as . What does the case give?
Theory UBC Math 100 §16.3Key results
Corrected working
Strategy
Solve the Lagrange system by factoring rather than dividing, so that every case is kept, then compare f at all the candidates.
Working
Factor, and follow both cases.
The case the student found.
The case lost by dividing.
The circle is closed and bounded, so both extremes exist; compare all four candidates.
Answer
The answer is 27, at the points (0, 3) and (0, −3).
Check
On the circle x² = 9 − y², so f = 9 + 2y², which is largest when y² = 9, giving 27.
Where this goes wrong
Dividing a Lagrange equation by a variable, which throws away the points where that variable is zero. Here those points are exactly where the maximum is.
Leans on
Solving equations by factoring, from Functions, graphs and inverses
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