- Topic
- Related rates
- Difficulty
- Standard
- Suggested time
- 5 min
- Marks
- 3
Related rates practice question 11
At noon, ship A is 30 km due north of a port and sailing north at 20 km/h, while ship B is 40 km due east of the same port and sailing east at 15 km/h. How fast is the distance between the ships increasing at noon?
Give the answer in kilometres per hour.
One ship heads north and the other east, so the port and the two ships form a triangle. What kind of triangle is it, and which side is the distance you want?
Let be B’s distance east and be A’s distance north. The distance between them is , so at every instant.
Differentiate , then substitute , , , , and .
A number.
Theory UBC Math 100 §5CLP-1 §3.2Key results
Worked solution
Strategy
The two ships and the port form a right triangle at every instant, so Pythagoras relates the distance to the two legs. Differentiate that relation, then substitute the instant.
Working
Differentiate with respect to time.
The distance at the instant in question.
Substitute.
Answer
The answer is 24 kilometres per hour.
Check
24 km/h is below 25 km/h, the fastest the gap can grow, and positive because both ships move away.
Where this goes wrong
Computing √(20² + 15²) = 25 as if the relative speed were the hypotenuse of the two speeds. That is right only when the ships’ positions are in the same ratio as their speeds, as they would be had both just left the port together. Here they are not, so their positions matter.
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