- Difficulty
- Standard
- Suggested time
- 4 min
- Marks
- 3
The chain rule and logarithms practice question 17
Let . Find .
Count the layers in . Which operation is done last, and which sits innermost?
Three layers: a cube on the outside, then sine, then inside. Differentiate from the outside in, one factor per layer.
, with . The last factor, , is the one most often lost.
A formula in x. Use ^ for powers and brackets for every input: sin(2x), e^(x^2), log(x+1). Give exact values: 1/6, not 0.167.
Theory UBC Math 100 §4.3CLP-1 §2.9Key results
Worked solution
Strategy
Peel the layers from the outside in. Each layer is differentiated with everything inside it left alone, and contributes one factor.
Working
The cube is the outermost layer, then the sine, then πx².
Power rule on the outside, with the sine left as it is.
Chain rule again on the middle layer: cosine at the inside, times the derivative of πx².
Multiply the three factors; 3 · 2πx = 6πx.
Answer
The answer is 6 pi x times sine squared of pi x squared, times cosine of pi x squared.
Check
Near x = 0, sin u ≈ u, so f ≈ π³x⁶ with derivative 6π³x⁵, and the formula is ≈ 6πx · π²x⁴ = 6π³x⁵ there too.
Where this goes wrong
Stopping at 3 sin²(πx²) cos(πx²), which differentiates two layers and forgets the innermost one, πx². Three layers give three factors.
Leans on
Derivatives of the trigonometric functions, from Exponential and trigonometric functions
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