The chain rule and logarithms practice question 4

This logarithm has base 2, and the derivative you know for $\log$ is for the natural logarithm only. How can you rewrite $\log_{2}$ in terms of $\log$?

Change the base: $\log_{2}u = \dfrac{\log u}{\log 2}$, and $\log 2$ is a constant.

Then use the chain rule on the natural logarithm: $\dfrac{d}{dx}\log\!\left(x^{3} + 1\right) = \dfrac{3x^{2}}{x^{3} + 1}$.