L’Hôpital’s rule practice question 11

What do $\sin(5x)$ and $e^{2x} - 1$ each tend to at 0? If you differentiate, watch for the constants the chain rule brings out.

Form $\tfrac{0}{0}$. Differentiate: $5\cos(5x)$ over $2e^{2x}$.

Both pieces are 1 at $x = 0$ apart from their constants.