- Difficulty
- Standard
- Suggested time
- 3 min
- Marks
- 2
Implicit differentiation and inverse trigonometric functions practice question 13
Find the exact value of the expression below.
Give the inner angle a name. What is its tangent, and in which range of angles must it lie?
Let , so with . Picture a right triangle with opposite side and adjacent side .
The hypotenuse is . Cosine is positive for every angle strictly between and , which settles the sign.
An exact expression, or a decimal to three decimal places.
Theory UBC Math 100 §4.7CLP-1 §2.12Key results
Worked solution
Strategy
Name the angle θ = arctan(−2), so that tan θ = −2, and find cos θ from a Pythagorean identity. The range of arctan decides the sign of the root.
Working
arctan returns an angle between −π/2 and π/2; a negative tangent puts it below 0, where sine is negative and cosine is positive.
Divide sin²θ + cos²θ = 1 through by cos²θ.
cos θ > 0 on (−π/2, π/2), so take the positive root.
Answer
The answer is 1 over root 5, about 0.447.
Check
arctan(−2) ≈ −1.107 lies in (−π/2, 0), where cosine is positive, and cos(−1.107) ≈ 0.447.
Where this goes wrong
Giving −1/√5 because the argument is negative. arctan(−2) lies between −π/2 and 0, where cosine is positive; only the sine of that angle is negative.
Leans on
Trigonometric identities, from Functions, graphs and inverses
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