- Difficulty
- Challenging
- Suggested time
- 6 min
- Marks
- 4
Implicit differentiation and inverse trigonometric functions practice question 21
Verify that the point lies on the curve below, then find the equation of the tangent line there.
Give the tangent line in any correct form, then compare against the model solution.
The right-hand side is a product of and , so it needs the product rule as well as the chain rule.
Differentiating both sides gives . Solve for , substitute to get the slope , then use .
Theory UBC Math 100 §4.5CLP-1 §2.11Key results
Worked solution
Strategy
Confirm the point is on the curve, differentiate implicitly to get a slope formula in x and y, evaluate it at the point, and assemble the point-slope form.
Working
Both sides agree, so the point does lie on the curve.
Differentiate both sides. The right-hand side is a product, so it splits into two terms.
Move every dy/dx term to the left and everything else to the right.
Divide, then cancel the common factor of 3.
Substitute the point to get the numerical slope.
Point-slope form. Equivalently y = (4/5)x + 12/5.
Answer
The answer is y − 4 = (4/5)(x − 2), equivalently y = 0.8x + 2.4.
What earns the marks
- Checks the point satisfies the equation: 8 + 64 = 72 and 9(2)(4) = 72.
- Differentiates implicitly, applying the product rule to the right-hand side.
- Solves for dy/dx and substitutes both coordinates to get a slope of 4/5.
- States a correct equation for the tangent line, such as y − 4 = (4/5)(x − 2).
Check
The curve also passes through about (2.01, 4.0080), a rise of about 0.008 over a step of 0.01, a slope of about 0.8 = 4/5.
Where this goes wrong
Differentiating 9xy as 9·dy/dx, treating x as a constant. It is a genuine product, so it differentiates to 9y + 9x·dy/dx.
Leans on
Equation of a tangent line, from The definition of the derivative
Try a similar question
The point lies on the curve below. Find at that point.Saved in this browser only.