- Topic
- Limits
- Difficulty
- Standard
- Suggested time
- 4 min
- Marks
- 2
Limits practice question 13
Find the horizontal asymptote of the graph of the function below as : enter the value of it approaches.
Divide out the dominant power of from the top and the bottom. What changes when you take out of a square root and is negative?
Take out of the root: . What is when is negative?
Check the sign before computing: for very negative , the root is positive and is negative.
A fraction or a decimal.
Theory UBC Math 100 §2.2CLP-1 §1.5Key results
Worked solution
Strategy
Divide out the dominant power of x from the top and the bottom. The root hides an absolute value, √(x²) = |x|, and on the far left |x| = −x, which sets the sign.
Working
The square root of x² is |x|, not x.
On the left |x| = −x, and the x cancels with the x taken out of the denominator.
The terms in 1/x and 1/x² vanish.
For the whole picture: on the right |x| = x gives y = 3/2, and the vertical asymptote is x = 1/2, where the root is not zero.
Answer
The answer is y = −3/2, or −1.5.
Check
At x = −100 the top is about 300 and positive while the bottom is −201, so f ≈ −1.49, close to −1.5.
Where this goes wrong
Writing √(9x²) = 3x and getting 3/2 at both ends. For negative x, √(9x²) = 3|x| = −3x: the top stays positive while the bottom is negative, so the left end is at −3/2.
Leans on
Square roots and absolute value, from Functions, graphs and inverses
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